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Voltage divider calculator

Solve for Vout, or start from the Vout you want and get the five best standard resistor pairs — with the error, the current they burn and the range they will really give you at ±1, 5 or 10 %.

Mode

Accepts 4k7, 4.7k, 10µ, 2R2.

Voltage divider Live
+ − VIN — I = — R1 — — R2 — — RL — — 0 V
VOUT —
— —
Field solver: solve ∇·(ε∇V) = 0 over the cross-section twice (real dielectrics, then vacuum) for C and C₀: Vout = Vin · (R2 ∥ RL) / (R1 + R2 ∥ RL) embeddedera.com/tools

Best standard pairs

The formula

Field solver: solve ∇·(ε∇V) = 0 over the cross-section twice (real dielectrics, then vacuum) for C and C₀: Z0 = 1 / (c·√(C·C₀)), Eeff = C / C₀ Pair: Zdiff = 2·Zodd, Zcomm = Zeven / 2 Instant first answer: Hammerstad–Jensen / Kirschning–Jansen / Cohn closed forms, bare copper

When to use it

A resistive divider is the right tool for sensing a voltage — battery monitoring on an ADC pin, a feedback node, a logic-level reference that draws next to nothing. It is the wrong tool for powering anything: the output moves with the load, and the resistors dissipate the full divider current all the time. If the load current is not far below the divider current, use a regulator.

Pitfalls

  • Tolerance stacks: two 5 % resistors give up to about ±5 % on Vout in the worst direction, which is why the table shows the real range, not just the nominal value.
  • A load in parallel with R2 lowers Vout. Enter it and the table recomputes; the rule of thumb is a divider current at least ten times the load current.
  • High-value dividers (megohms) save battery but feed an ADC slowly: check the ADC’s input impedance or add a capacitor across R2.
  • The same ratio in a different decade is the same divider. Set the current or total resistance range to pick the decade you can afford.

Need the whole board designed, not just the divider?